Math, asked by jayeshmore46, 2 months ago

Find the total conductance and resistance of four
parallel resistors having ressistances of 1, 0.5, 0.25
and 0.125 ohm? ​

Answers

Answered by preetipatel123
2

Answer:

total resistance =1.875/0.125

Step-by-step explanation:

R= 1+1/0.5+1/0.25+1/0.125

Answered by hukam0685
0

The total conductance (G) of parallel registers is 15 mho and total resistance(R) is 0.067 ohm.

Given:

  • Four parallel resistors.
  • 1 ohm, 0.5ohm, 0.25 ohm and 0.125 ohm

To find:

  • Find the total conductance and resistance of the circuit.

Solution:

Conductance of parallel combinations of resistors:

Conductance of parallel combination of resisters is addition of individual conductance.

\bf G =  \frac{1}{R_1}  + \frac{1}{R_2} +\frac{1}{R_3} + ... + \frac{1}{R_n}  \:  \: \mho \\

Resistance of parallel combinations of resistors:

\bf R =  \frac{1}{G} \\

Step 1:

Find the conductance of the circuit.

G =  \frac{1}{1}  + \frac{1}{0.5} +\frac{1}{0.25} + \frac{1}{0.125} \\

G =  \frac{1}{1}  + \frac{10}{5} +\frac{100}{25} + \frac{1000}{125} \\

G =1  + 2+4 +8 \\

\bf G = 15  \: \mho

Thus,

Conductance of circuit is 15 'mho'.

Step 2:

Find the total resistance of the circuit.

As we know that resistance is reciprocal of conductance or vice versa.

So,

R =  \frac{1}{15}  \: ohm \\

\bf R = 0.067 \:  \: ohm \\

Thus,

The equivalent resistance of the circuit is 0.067 ohm.

Thus,

The conductance of circuit is 15 mho and resistance is 0.067 ohm.

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