Question

Find the total no. Of orbitals in nickel which have m <_ 1 and at least one electron is present, where "m" is magnetic quantum number

Answer 1

Answer:

6

Explanation:

Conventionally, the location of an electron is written in the following way,

n, l, ml, ms

n represents the principal quantum number,

l represents the azimuthal quantum number,

ml represents the magnetic quantum number

ms represents the spin quantum number.

The absolute value of the magnetic quantum number must be less than or equal to that of the azimuthal quantum number. This means that the azimuthal quantum number must be greater than or equal to 1 (according to your question). Because the azimuthal quantum number must be less than that of the principal quantum number, the principal quantum number must be greater than or equal to 2.

Remember that the azimuthal quantum number corresponds to the subshell.

0 - s subshell, 1 - p subshell, 2 - d subshell, 3 - f subshell,

The ground state electron configuration of nickel is 1s2 2s2 2p6 3s2 3p6 4s2 3d8

Now, time to find electrons in orbitals that fit our requirements. First, n≥2, this gives us:

2s 2p 3s 3p 4s 3d

Second, l≥1, this gives us:

2p 3p 3d

Because we want the magnetic quantum number to be only 1 or -1, there are two possibilities for orbitals each that fulfill the requirements.

This gives us 2 + 2 + 2 or

6 possibilities.

Answer 2

Answer:

There are 6 orbitals in nickel which fulfil the given conditions.

Explanation:

• The location of an electron is typically expressed using the following symbols: n, l, ml, and ms, where n is the primary quantum number, l is the azimuthal quantum number, and ml is the magnetic quantum number. The spin quantum number is represented by ms.
• The magnetic quantum number must have an absolute value that is less than or equal to the azimuthal quantum number.
• The azimuthal quantum number must therefore be larger than or equal to 1 according to the question
• The main quantum number must be larger than or equal to 2, since the azimuthal quantum number must be lower than the principal quantum number.
• The subshell is corresponding to the azimuthal quantum number.
• 0 - s subshell, 1 - p shell, 2 - d shell, and 3 - f shell,
• Nickel has an electron configuration that is 1s2 2s2 2p6 3s2 3p6 4s2 3d8 in its ground state.
• First, n≥2 provides us with: 3s 3p 4s 3d 2s 2p
• Second, l≥1 provides us with: 2p 3p 3d
• Because we only want the magnetic quantum number to be either 1 or -1, each orbital can have one of two possible configurations.
• This gives us 6 alternatives as 2 + 2 + 2 = 6.

There can be 6 orbitals in nickel which fulfil the given conditions.

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