find the total number of dioginals in a polgyon having 8 sides
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hey ....
a square (or any quadrilateral) has 4(4−3)/2 = 4×1/2 = 2 diagonals. an octagon has 8(8−3)/2 = 8×5/2 = 20 diagonals......
in pic there is a polygon having 8 sides
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Answer:
20 diagonals
Step-by-step explanation:
The number of diagonals of an n-sided polygon is:
n(n − 3) / 2
=8(8 - 3) / 2
=8(5) / 2
=40/2
=20
I hope it may help you.
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