Question

Find the total resistance

Answer 1

Lets get started

R2 R3 and R4 are in series so the effective resistance is

R234-20+10+20=50

Now R6 is in parallel with Effective Resistance of (2,3and 4)

So their net effective resistance is

1/R(2346)=1/R(234) + 1/R6

so now putting the values we get

R(2346)= 1500/80=150/8=75/4

Now its in series with R1 and R5

so simply add to get equivalent resistance

Req=10+10 +75/4

solve it and u will get the answer

Answer 2

Let's take first the series resistance i.e R2, R3 and R4, 20+10+20=50 ohms

50 and 30 (R6) are in parallel

1/50+1/30=4/75

75/4ohms

Now this resistance is in series with R1 and R5

10+10+75/4=38.75ohms