Question

Find the total resistance and total current in the circuit diagram

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Answer 1

Answer:

R1 and R2 is in series. so,

r= R1 + R2

r= 3 +3

r= 6 ohm

now, r and R3 is in parallel. so,

r1 = r × R3/ r + R3

= 6 × 3 / 6+3

r1 = 18/ 9

r1= 2 ohm

Now, r1 , R4 and R5 is in series

so, total resistance = r1 + R4 + R5

= 2 + 0.5 + 0.5

= 3 ohm.

r is the resistance produced by series combination of R1 and R2.

r1 is the resistance produced by parallel combination of r and R3.

current I = V / R

I = 3/ 3

I = 1A.

Answer 2

Answer:

Total Resistance = 3 ohm Ω

Total Current = 1 Ampere

Explanation:

A ] Total resistance

the upper triangle has 3 resistors

2 in series and 1 in parallel

So ; the series one R1 and R2 forms an Equavalent resistance of 6 ohm

and the 6 ohm is in parallel with middle branch of 3 ohm R3 resistor.

R equivalent = R1 + R2 × R3 / R 1 + R2 + R3

= 6 × 3 / 3 + 3 + 3

R equivalent = 18 / 9 = 2 ohm .

★ Now the new resistance is in series with R4 and R5

it forms

R net = New resistance + R4 + R5 = 2 + 0.5 + 0.5 = 3 Ohm Ω

[ ★ Hence Total resistance is 3 Ω ★ ]

B ] Total Current

Voltage ( V ) = Current ( I ) × Resistance ( R )

★ Current = Voltage / resistance = 3 / 3 = 1 Ampere .

HOPE it helps you .