Question

find the total resistance of a circuit as shown. find the ammeter reading when circuit is closed when voltage us 2V​

Answer 1

$\large \bold{FOR \: TOTAL \: RESISTANCE}$

◼$\underline \bold{FOR \: SERIES \: COMBINATION }$

Two resistors of 3 ohn are in series

For a series combination resistance is,

$\boxed{R_s = R_1 + R_2 +n \: terms}$

$R_s = 3 + 3$

$R_s = 6 ohm$

◼$\underline \bold{FOR \: PARALLEL \: COMBINATION }$

When resistor are connected in series total resiatance will be

$\frac{1}{R_p } = \frac{1}{R_1} + \frac{1}{R_2 } + n \: terms$

Since , resistor of resiatance 3 ohm and $R_s$ of resistance 6 ohm is in parallel combonation so,

$\frac{1}{R_p } = \frac{1}{R_s} + \frac{1}{3}$

$\frac{1}{R_p } = \frac{1}{6} + \frac{1}{3}$

$\frac{1}{R_p } = \frac{1 + 2}{6}$

$\frac{1}{R_p } = \frac{3}{6}$

$\frac{1}{R_p } = \frac{1}{2}$

$R_p = 2 ohm$

$\bold{So \: net \: resistance \: is \: 2 ohm}$

$\large \bold{CURRENT}$

By ohm's law we know

$\boxed{\bold{Potential \: difference = Current \times Resistance}}$

$\boxed{ \textbf{P = V \times I}}$

Since,

$\bold{P = 2 \: v}$

$\bold{R = 2 \: ohm}$

$\boxed{ I = \frac{P}{V}}$

$\boxed{ I = \frac{2}{2}}$

$\bold{ Current \: in \: the \: circuit \: is \: 1 Amphere}$

Answer 2

Answer:- 1 A

Step by Step Solution:-

First of  all we need  to find  equivalent  resistance  of the given  circuit,

Here,

R₁ and R₂ are in series, So, there equivalent  resistance,

R' = R₁ + R₂

R' = 3 + 3

R' = 6 Ω

Now,

R' and R₃ are  in parallel, if the  total equivalent  resistance is  R,

1/R = 1/R' + 1/R₃

1/R = 1/6 + 1/3

1/R = 1/6 + 2/6

1/R = 3/6

1/R = 1/2

R = 2 Ω

We have,

R = 2 Ω

V = 2 V

I = ?

Using Om's Law,

V = IR

I =V/R

I = 2/2

I = 1 A