Question

find the total surface area and volume of a cube whose edge is 4 cm and 6 CM​

Answer 1

1] Find the total surface area of volume of a cube having edge 4cm.

$\underline{Solution :-}$

i) Total surface area (TSA) = 6 × (side)²

☛ TSA = 6 × (4)²

☛ TSA = 6 × 16

∴ $\boxed{\boxed{TSA\:=\:96\:cm^2}}$

ii) Volume (V) = (side)³

☛ V = (4)³

∴ $\boxed{\boxed{Volume\:=\:64\:cm^3}}$


2] Find the total surface area of volume of a cube having edge 6cm.

$\underline{Solution :-}$

i) Total surface area (TSA) = 6 × (side)²

☛ TSA = 6 × (6)²

☛ TSA = 6 × 36

∴ $\boxed{\boxed{TSA\:=\:216\:cm^2}}$

ii) Volume (V) = (side)³

☛ V = (6)³

∴ $\boxed{\boxed{Volume\:=\:216\:cm^3}}$

Answer 2

$\underline{\mathfrak{\huge{The\:Question:}}}$

Find the total surface area and the volume of a cube whose:

a ) Edge is 4 cm

b ) Edge if 6 cm

$\underline{\mathfrak{\huge{Your\:Answer:}}}$

a ) We know that the Total surface area of a cube = $\tt{6a^{2}}$

Where, a = the edge or the side of the given cube

Total surface area = 6 × 4 × 4

=》 Total surface area = 6 × 16

=》 Total surface area = $\boxed{\tt{96\:cm^{2}}}$

The volume of a cube = $\tt{a^{3}}$

Where, a = the edge or the side of the given cube

Volume = 4 × 4 × 4

=》 Volume = 4 × 16

=》 Volume = $\boxed{\sf{64\:cm^{3}}}$

b ) We know that the Total surface area of a cube = $\tt{6a^{2}}$

Where, a = the edge or the side of the given cube

Total surface area = 6 × 6 × 6

=》 Total surface area = 6 × 36

=》 Total surface area = $\boxed{\tt{216\:cm^{2}}}$

The volume of a cube = $\tt{a^{3}}$

Where, a = the edge or the side of the given cube

Volume = 6 × 6 × 6

=》 Volume = 6 × 36

=》 Volume = $\boxed{\sf{216\:cm^{3}}}$