Question

Find the total surface area of a building whose dimensions are 30m,20m, and 40m. The walls , floor and the roof of this building are to be repaired the contractor asks for ₹.40 per square metre. What will be the estimate of the contractor for this work

Answer 1

Answer:

l = 30m

b = 20m

h = 40m

Total surface area = 2(lb+bh+hl)

=2(30*20+20*40+40*30)

=2(600+800+1200)

=2*2600

=5200m^2

Cost of repairing the walls, floor and roof for 1m^2= Rs 40

Cost of repairing the walls, floor and roof for 5200m^2

=5200*40

= Rd 20800

Answer 2

l=30m
b=20m
h=40m

Total surface area=2(lb+bh+hl)
=2(30*20+20*40+40*30)
=2(600+800+1200)
=2(2600)
=5200m^2


Cost to repair=rate*total surface area
=40*5200
=Rs.208000

Hence he would require Rs.208000