find the total surface area of a closed cardboard box of length 0.5 m , breadth 25 cm & hight 15 cm
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TSA = 2 (lb+bh+LH)
= 2 ( 50x 25 +25x15+ 50x 15)
= 2 ( 1250+ 375+750)
= 2 x 2375
= 4750cm²
= 2 ( 50x 25 +25x15+ 50x 15)
= 2 ( 1250+ 375+750)
= 2 x 2375
= 4750cm²
demonsking52801:
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Answered by
1
area of cuboid =2(lb + bh +hl) (o.5m =50 cm)
= 2(50×25+25×15+15×50)
= 2(1250+375+750)
= 2(2375)
= 4750 cm²
= 2(50×25+25×15+15×50)
= 2(1250+375+750)
= 2(2375)
= 4750 cm²
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