Question

Find the total surface area of a cube whose volume is 3√3a^3 cubic units.

Plz those who know only they will answer...Crct answer will be marked as brainliest...Plz give the crct one.

Answer 1

Volume = edge^3

3√3 = edge^3

edge = √3 units

So
Total surface area = 6*edge^2
= 6*(√3)^2
= 6*3
= 18 sq.units

Answer 2

Given volume of the cube = $3 \sqrt{3} a^3$

We know that volume of the cube = $s^3$

$s^3 = (\sqrt{3}a)^3$

$s = \sqrt{3} a$


We know that TSA of a cube = 6s^2

                                                 = $6( \sqrt{3} a)^2$

                                                 = 18a^2.


Therefore the TSA of a cube = 18a^2 sq.units


Hope this helps!