find the total surface area of a hollow cylinder open at both ends if its lengtg is 28cm external radius is 7cm & thickness is 1cm (ans--2369.71cm²)
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Step-by-step explanation:
external radius (R) = 7cm
so total external surface area = 2πRh
= 2 ×3.14×7×28 = 1230.88 cm²
now
internal radius (r) = R - thickness
= 7-1 = 6cm
now internal surface area = 2πrh
= 2×3.14×6×28 = 1055.04cm²
now total area = 1230.88+1055.04
= 2285.92cm²
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