Question

Find the total surface area of a hollow cylinder open at both ends if its length is 12cm external diameter is 8 cm and the thickness is 2cm.

Answer 1

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Answer 2

Answer:

is 528 cm²

Step-by-step explanation:

TSA=2πRH+2πrh+(2πR²-2πr²)

now put the value in this formula H=12;R¹=4,r²=2

in this formula take common ok

2πh(R+r)+2(πR²-πr²)

now take again common (2π) show you see 2π(hR+hr)+(R²r²)

=now,put the value 2×22/7×(12×4+12×2)+(4²-2²)

=2×22/7×(48+24)+(16-4)

=2×22/7×(72)+(12)

=2×22/7×84

=2×22×12

=44×12=528

528cm²