Question

Find the total surface area of a hollow hemispherical bowl of diameter 14cm and negligible thickness

Answer 1

Dear Student,

● Answer -

TSA = 616 cm^2

● Explanation -

# Given -

d = 14 cm

# Solution -

Radius of hemispherical bowl is -

r = 14 / 2

r = 7 cm

Inner surface area of hemispherical bowl is 2πr^2 and outer surface area of hemispherical bowl is 2πr^2.

Total surface area (inner + outer) of bowl is -

TSA = 2πr^2 + 2πr^2

TSA = 4πr^2

TSA = 4 × 22/7 × 7^2

TSA = 4 × 22 × 7

TSA = 616 cm^2

Hence, total surface area of hollow hemispherical bowl is 616 cm^2.

Thanks dear. Hope this helps you...

Answer 2

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Step-by-step explanation:

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