Question

Find the total surface area of an open pipe of
length 50 cm, external diameter 20 cm and
internal diameter 6 cm.​

Answer 1

SOLUTION:-

Given:

⚫Height of the pipe is 50cm.

⚫External diameter is 20cm

⚫Internal diameter is 6cm

Therefore,

⚫External radius= 20/2 = 10cm

⚫Internal radius= 6/2 = 3cm

Now,

We know that, total surface area of the cylinder;

$= > 2\pi h(r + r) + 2r( {r}^{2} - {r}^{2} )$

So,

$= > 2 \times \frac{22}{7} \times 50 \times (10 + 3) + 2 \times \frac{22}{7} \times ( {10}^{2} - {3}^{2} ) \\ \\ = > \frac{44}{7} \times 50 \times 13 + \frac{44}{7} \times (100 - 9) \\ \\ = > \frac{28600}{7} + \frac{44}{7} \times 91 \\ \\ = > \frac{28600}{7} + \frac{4004}{7} \\ \\ = > \frac{32604}{7} {cm}^{2} \\ \\ = > 4657.71 {cm}^{2}$

Thus,

The total surface area is 4657.71cm².

Hope it helps ☺️

Answer 2

Answer:

he or she had explained. well

Step-by-step explanation:

just go through it