Question

Find the total surface of a drinking glass in shape of a frustum of a cone whose diameters at the ends are 6.50 cm and 3.50 cm and the perpendicular height of tumbler is 7.80 cm.

Answer 1

by using total surface area of frustum..

....

Answer 2

The total surface of a drinking glass in shape of a frustum of a cone is 167.638 sq.cm.

Step-by-step explanation:

Diameter of bigger end = 6.50 cm

Radius of bigger end R= $\frac{6.5}{2}=3.25 cm$

Diameter of smaller end = 3.5 cm

Radius of smaller end r= $\frac{3.5}{2}=1.75 cm$

Height of frustum = 7.8 cm

Total surface area of frustum = $\pi (R+r)(\sqrt{(R-r)^2+h^2})+\pi R^2 + \pi r^2$

Total surface area of frustum =$\frac{22}{7} (3.25+1.75)(\sqrt{(3.25-1.75)^2+7.8^2})+\frac{22}{7} \times 3.25^2 + \frac{22}{7} \times 1.75^2=167.638 cm^2$

Hence the total surface of a drinking glass in shape of a frustum of a cone is 167.638 sq.cm.

#Learn more:

The shape of frustum of a cone of height 21 cm. The radii of its two circular ends are 3 cm and 2 cm. Find the capacity of the glass and curved surface area of frustum.

https://brainly.in/question/15143118