Question

find the total surface of the hollow cylinder open at the both ends if the length is 12 cm and the external diameter is 10 cm and thickness is 2 cm​

Answer 1

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Step-by-step explanation:

Given:-

Outside cylinder radius = 5cm

Height of outside and Inside cylinder = 12cm

Inside cylinder radius = 5cm-2cm

= 3cm

Cylinders are open at both end so we use curved surface are of a cylinder

$2\pi rh$

CSA Of Outside Cylinder = 2×22/7×5×12

=

$\frac{2640}{7} {cm}^{2}$

CSA Of Inside Cylinder = 2×22/7×3×12

=

$\frac{1584}{7} {cm}^{2}$

CSA of the hollow cylinder = CSA of outside cylinder - CSA of inside cylinder

=

$\frac{2640}{7} - \frac{1584}{7}$

=

$1166 {cm}^{2}$