Math, asked by Rishabh9612, 1 year ago

find the trigonometric functions of 0°​

Answers

Answered by simran182003
42

sin(0°)= 0

cos(0°)= 1

sec(0°)=1

tan(0°)=0

cot(0°)=not defined

csc(0°)= not defined

Explanation:

Using a triangle in standard position with the angle involved at the origin,

the 6 basic trigonometric functions are defined as

sin = perpendicular/ hypotenuse

cos = base/hypotenuse

tan = perpendicular/base

sec= hypotenuse/ perpendicular

csc=hypotenuse/base

cot= base/ perpendicular

This gives the values as in the "Answer" for the 6 basic trig functions.

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Answered by akanksha9775
7

Angle of measure=0° m<XOP=0°

P(1,0) i.e x=1 and y=0 \sin0 {}^{o } = y  = 0 \\  \cos0 {}^{o} = x = 1 \\  \tan0 {}^{o} =  \frac{0}{1} =0 {}^{} \\cot \: 0 {}^{o} =  \frac{1}{0} = (not \: defined)\\sec \:  {0}^{o} =  \frac{1}{1} = 1 \\ cosec =  \frac{1}{0} = 0 = (not \: defined)

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