Question

find the trigonometric ratios for following triangle ​

Answer 1

Answer:

Answer is below.....

Step-by-step explanation:

sin 45 = Opposite/Hypotenuse = x/x√2=1/√2

cos 45 = Adjacent/Hypotenuse = x/x√2 = 1/√2

tan 45 = Opposite/Hypotenuse = x/x=1

cosec 45 = 1/sin 45 = √2

sec 45 = 1 / cos 45 = √2

cot 45 = 1 / tan 45 =1

Hope it helps!

<3

Answer 2

Step-by-step explanation:

sin45 = BC/AC = x/$\sqrt{2$x = 1/$\sqrt{2$

cos45 = AB/AC = x/$\sqrt{2$x = 1/$\sqrt{2$

tan45 = BC/AB = x/x = 1

cosec45 = AC/BC = $\sqrt{2$ x/x = $\sqrt{2$

sec45 = AC/AB =$\sqrt{2$ x/x = $\sqrt{2$

cot45=  AB/BC= x/x = 1

For reference  :

sin∅ = opposite side/hypotenuse

cos∅ = adjacent side/hypotenuse

tan∅ = opposite side / adjacent side

cosec∅ =  hypotenuse/ opposite side

sec∅ = hypotenuse/adjacent side

cot∅  = adjacent side/opposite side

mark me brainliest if u understood