Question

Find the triplets whose square sum is less than a given value

Answer 1

●(3, 4, 5)
$3 ^{2} = 9$
$4 ^{2} = 16$

$5 ^{2} = 25$
then By PGT
$5 ^{2} = 4 ^{2} + 3 ^{2}$
25=16+9
25=25
Therefore this is a Pythagorean triplet