Find the TSA of tent in which R =3,5 HEIGHT OF CUBOID AND CONE =3,5
IN THE PLACE WHERE I HAVE PUT THE COMMA THERE WILL BE POINT
Answers
Step-by-step explanation:
Radius of base of cylindrical portion=14m
Height of cylindrical portion=3m
Curved surface area of cylindrical part=2×
7
22
×14×3
Height of conical part=13.5−3=10.5m
For conical part:r=14m,h=10.5m
l=
(14)
2
+(10.5)
2
=
306.25
l=17.5m
CSA of conical part=πrl=
7
22
×14×17.5=770㎡
∴Total area to be painted=(264+770)㎡=1034㎡
Cost of painting=Rs. (1034×2)=Rs. 2068
Step-by-step explanation:
Answer:
Surface Areas
Cuboid: 2(lb+bh+hl), where l, b and h are the length, breadth and height of a cuboid.
Cube: 6a2, a is the side of the cube.
Cylinder: 2πr (r+h), r is the radius of circular base and h is the height of the cylinder.
Cone: πr(l+r), r is the radius of the circular base, l is the slant height of the cone.
Sphere: 4πr2, r is the radius of the sphere.
Hemisphere: 3πr2, r is the radius of the hemisphere.
Volumes
Cuboid: l × b × h, where l , b and h are the length, breadth and height of a cuboid.
Cube: s3, s is the side of the cube.
Cylinder: πr h, r is the radius of circular base and h is the height of the cylinder.
Cone: 1/3 πr 2h, r is the radius of the circular base, l is the slant height of the cone.
Sphere: 4/3 πr3, r is the radius of the sphere.
Hemisphere: 2/3 πr3, r is the radius of the hemisphere.