find the two complementary angles differ by 44 degree
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Answered by
18
Let One angle be = x ° (let it be bigger)
Another be = 90 °- x °
( As they were complementary)
Now, if they differ by 44
means,
x °- ( 90 °- x° ) = 44 °
=> x °- 90 ° + x ° = 44 °
=> 2x ° = 44 ° + 90 °
=> x ° = 134 °/ 2
=> x° = 67 °
Hence, required angles be equals to :
67 ° and 90 ° - 67 ° = 23 °
Another be = 90 °- x °
( As they were complementary)
Now, if they differ by 44
means,
x °- ( 90 °- x° ) = 44 °
=> x °- 90 ° + x ° = 44 °
=> 2x ° = 44 ° + 90 °
=> x ° = 134 °/ 2
=> x° = 67 °
Hence, required angles be equals to :
67 ° and 90 ° - 67 ° = 23 °
BrainlyPrincess:
bhaiyaa 134 ÷ 2 = 67
Answered by
9
Let the first angle be x
Let the second angle be 90 - x
Measure of complementary angles = 90°
A/q,
x - (90 - x) = 44
x - 90 + x = 44
2x - 90 = 44
2x = 44 + 90
2x = 134
x =
x = 67
1st angle => x => 67°
2nd angle => 90 - x => 90 - 67 => 23°
The two angles are of 67° and 23°
Let the second angle be 90 - x
Measure of complementary angles = 90°
A/q,
x - (90 - x) = 44
x - 90 + x = 44
2x - 90 = 44
2x = 44 + 90
2x = 134
x =
x = 67
1st angle => x => 67°
2nd angle => 90 - x => 90 - 67 => 23°
The two angles are of 67° and 23°
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