Question

find the two consecutive positive integers sum of whose squares is 365 ​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Let two consecutive numbers be x and x+1

A/Q

x^2+(x+1)^2=365

x^2+x^2+2x+1=365

2x^2+2x=364

2(x^2+x)=364

x^2+x=182

x^2+x-182=0

x^2+14x-13x-182=0

x(x+14)-13(x+14)=0

(x+14)(x-13)=0

x+14=0 or x-13=0

x=-14 or x=13

So numbers are 13 and 14