Question

What volume of water should be added to 1600 ml of a 0.205 N solution so that the resulting solution will be 0.2 N
(1) 40 mL
(2) 50 mL
(3) 100 mL
(4) 20 mL​

Answer 1

Answer:

40ml

Explanation:

using equation

N1V1= N2V2

0.205×1600 = 0.200× V2

V2 = 1640

this is total volume after adding water

so amount of water added

= final volume - initial volume

= 1640 -1600

=40ml

Hope it helps

Answer 2

Answer:

(1)40 ml i think

Explanation:

u r very prity