find the two consecutive positive integers sum of whose square is 613
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Answer:
x²+ (x+1)²= 613
2x²+2x=613
x²+x=306
Step-by-step explanation:
x²+18x-17x-306=0
x=17
consecutive number are 17 and 18
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An integer is a whole number not a fractional number that can be positive , negative , or zero .
A square number or perfect square is an integer that is the square of an integer ; in other words , it is the product of some integer with itself .
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