Question

find the two digit number which has square of the sum of it's digit equal to the number obtained by reversing it's digit​

Answer 1

Answer:

Step-by-step explanation:Bro it's 8

Answer 2

Answer:

Step-by-step explanation:

1 + 2b + b^2 = 10b + 1

:

b^2 + 2b - 10b = 1 - 1

b^2 - 8b = 0

divide both sides by b

b - 8= 0

b = 8

then the number is 18; (9^2 = 81)

:

I don't think there is any other number, except perhaps 10

(1+0)^2 = 0 + 1