Question

Find the two no such that the sum of twice the first and thrice the second is 92 and four time the first exceed seven time the second by 2

Answer 1

Answer:

Step-by-step explanation:

let the two numbers  be X and Y

according to the question

- sum of twice the first and thrice the second is 92,that can be expressed as

2X+3Y=92........(i)

-Also, four time the first exceed seven times the second by 2,which can be expressed as

4X-7Y=2..........(ii)

solving (i) and (ii) we get

Y=14

X=25