find the two numbers such that one of them exceeds the other by 8 and their sum their sum is 90
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Answer :-
Let first number be x
and second number be x + 8 ( exceeds by 8 )
The sum of both numbers is 90
So ,
So , first number = 41
second number = x + 8 = 41 + 8 = 49
Numbers are 41 and 49.
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