Question

find the two numbers such that one of them exceeds the other by 9 and their sum is 81

Answer 1

Here is your answer

Let the number is x

Other number is x + 9


ATQ
$x + x + 9 = 81 \\ 2x = 81 - 9 \\ 2x = 72 \\ x = \frac{82}{2} \\ x = 41$
Therefore One Number is 41

And other number is 41+ 9 = 50

Hope it helps you

Answer 2

Hi friends
Here is your answer

Let the number is x

$x + x + 9 = 81 \\ 2x = 81 - 9 \\ x = \frac{72}{2} \\ x = 36$
II Number is 36 + 9 = 45

Hope it helps