Find the two numbers which are in the ratio 3:5 and their sum is 232
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Answered by
0
3x+5x =232
8x=232
x=29
hope it helps you. . .
8x=232
x=29
hope it helps you. . .
Anonymous:
hi
Answered by
2
Let the two numbers be x and y
Given that x:y = 3:5
x/y = 3/5
5x = 3y
5x - 3y = 0 (equation 1 )
Sum of the numbers = 232
x + y = 232 (equation 2)
Taking 1 and 2 as simultaneous equations
5x - 3y = 0
x + y = 232
5x - 3y = 0
5x + 5y = 1160
subtracting 2 from 1
5x - 3y = 0
-5x - 5y = - 1160
- 8y = - 1160
y = 145
x + 145 = 232
x = 87
The numbers are 145 and 87.
Given that x:y = 3:5
x/y = 3/5
5x = 3y
5x - 3y = 0 (equation 1 )
Sum of the numbers = 232
x + y = 232 (equation 2)
Taking 1 and 2 as simultaneous equations
5x - 3y = 0
x + y = 232
5x - 3y = 0
5x + 5y = 1160
subtracting 2 from 1
5x - 3y = 0
-5x - 5y = - 1160
- 8y = - 1160
y = 145
x + 145 = 232
x = 87
The numbers are 145 and 87.
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