Question

find the two numbers whose difference is 3 and the sum of whose square is 117​

Answer 1

Answer:

6 and 9

Step-by-step explanation:

9 - 6 = 3

6*2+ 9*2 =117

*2 = square 2

Answer 2

Given:–

Sum of squares = 117

The two natural numbers differs by 3

To find:–

Two natural numbers

Concept:–

Simple equations (based on quadratic equation)

Step by step explaination:–

Let us assume the first number be y. Therefore, second number will be (y+3).

According to the question.

⟼ y² + (y+3)² = 117

Now, opening brackets and solving.

⟼ y² + y² + 6y + 9 = 117

⟼ 2y² + 6x - 108 = 117

⟼ y² + 3y - 54 = 0

⟼ (y+9) (y-9) = 0

Therefore,

⟼ y = -9 and 6

Answer:–

6 is accepted as -9 is not a natural number and being negative it can't be accepted.

Second number = 6+3 ⟼ 9