Question

find the two parallel side of a trapizium whose area is 1.6 m altitude is 10 dm​

Answer 1

Step-by-step explanation:

Let smaller parallel side = x

Longer parallel side = x+8

Area of trapezium = 1/2 × h(d1 + d2)

1/2 × 10(x + x + 8) = 160

5(2x + 8) = 160

10x + 40 = 160

10x = 160 - 40

x = 120/10 = 12dm

So,

Parallel sides are :

d1 = x = 12dm

d2 = x + 8 = 20dm

I hope it's useful