Question

find the two quadratic solutions of x²+x-12=0​

Answer 1

Answer:

x^2+x-12=x^2+4x-3x-12

=x(x+4)-3(x+4)

=(x+4)(x-3)

x+4=0 or x-3=0

x=-4 or x=3 are the solutions of the given quadratic polynomial.

Answer 2

Answer:

3 and -4

Step-by-step explanation:

x2+x-12

=x2+4x-3x-12

=x(X+4)-3(x+4)

=(x-3)(X+4)