find the two quality concept in natural numbers sum of whose squares is 85
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Let the two consecutive natural numbers be ‘x’ and ‘x + 1’
⇒ Given that the sum of their squares is 85.
Then by hypothesis, we get
2 + ( + 1)2 = 85
⇒ 2 + 2 + 2 + 1 = 85
⇒ 22 + 2 + 1 − 85 = 0
⇒ 22 + 2 + 84 = 0 ⇒ 2 [2 + − 42 ] = 0
⇒ 2 + 7 - 6 - 42 = 0 [by the method of factorisation]
⇒ ( + 7) - 6( + 7) = 0
⇒ ( - 6)( + 7) = 0
⇒ = 6 or = 7
Case i: if x = 6 x + 1 = 6 + 1 = 7
Case ii: If x = 7 x + 1 = -7 + 1 = -6
∴ The consecutive numbers that the sum of this squares be 85 are 6,7 and -6, -7.
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