find the two supplementary angles if one exceeds the other by 18?
Answers
Answered by
0
let one be x and other be x+18
x+x+18=360 degree
2x+18=360 degree
2x=360-18
2x=342
x=342÷2
x=171
therefore one supplementary angle is 171 and the supplementary angle is 189.
x+x+18=360 degree
2x+18=360 degree
2x=360-18
2x=342
x=342÷2
x=171
therefore one supplementary angle is 171 and the supplementary angle is 189.
buddy578:
is this the ans
Answered by
12
Hello !!
Let one angle be X.
Other angle = ( 180 - X ).
A/Q
X + 18 = 180 - X
X + X = 180 - 18
2X = 162
X= 162/2 = 81
One angle = X = 81°
And,
Other angle = 180 - X = 180-81 = 99°
Let one angle be X.
Other angle = ( 180 - X ).
A/Q
X + 18 = 180 - X
X + X = 180 - 18
2X = 162
X= 162/2 = 81
One angle = X = 81°
And,
Other angle = 180 - X = 180-81 = 99°
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