Find the unit place digit of ((137)^13)^47
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Answered by
2
Step-by-step explanation:
((137)^13)^47
137^611
The unit place is 3
Answered by
4
Power of 7 have units digit cycling through 7,9,3,1.
i.e.
7^1 => 7
7^2 => _9
7^3 => __3
7^4 => ___1
7^5 => ___7
and so on
137^13 = 137^12 * 137^1 = (137^4)^3 * 137^1 = 1^3 * 7 = 7
Again 7^47 = 7^44 * 7^3 = (7^4)^11 * 7^3 = 1 * 3
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