Question

Find the unit's digit in the product of
$\frac{ {2}^{32} \times {3}^{42} \times {847}^{42} }{ {9}^{14} }$
with explanation ​

Answer 1

Answer:

2^32 = divide 32 with 4 and it's remainder is new power of

2

So,

=> 2^0 = 2^4 = 6

●_______2nd step

=> 3^43 divide 43 by 4 and it's remainder is new power of 3

=> 3^3 = 7

●________3rd step

=> 847^42 = divide 42 by 4 and its remainder is new power of

7

=> 7^2 = 9

●_______4th step

=> 9^14 even multiple so it's unit digit is 1

=> 1

☆____For Question

=> (2 ^32 × 3^43 × 847^42) ÷ 9^14

=> (6 × 7 × 9)÷1

=> 6

Step-by-step explanation:

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