Question

Find the units digit in the product of
$(2 {}^{32} \times 3 {}^{43} \times 847 {}^{42} )\div 9 {}^{14}$
​

Answer 1

Answer:

dont know sorry.... ok

Answer 2

Step-by-step explanation:

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

$\boxed{\bf{\pink{\bigstar Given \longrightarrow}}}$

=> (2 ^32 × 3^43 × 847^42) ÷ 9^14

$\boxed{\bf{\pink{\bigstar Solution \longrightarrow}}}$

●______1st step

=> 2^32 = divide 32 with 4 and it's remainder is new power of

2

So,

=> 2^0 = 2^4 = 6

●_______2nd step

=> 3^43 divide 43 by 4 and it's remainder is new power of 3

=> 3^3 = 7

●________3rd step

=> 847^42 = divide 42 by 4 and its remainder is new power of

7

=> 7^2 = 9

●_______4th step

=> 9^14 even multiple so it's unit digit is 1

=> 1

☆____For Question

=> (2 ^32 × 3^43 × 847^42) ÷ 9^14

=> (6 × 7 × 9)÷1

=> 6

$\huge\textbf{Answer = 6}$