find the unknow angles marked in each of the following figures.
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here
angle 1= 110
<BAC= 180-110....by linear pair
=><BAC=70°
now <DCA=120°
similarly by linear pair
<BCA=60°
now in triangle ABC
<A+<B+<C=180.....ANGLE SUM PROPERTY
70+<B+60=180
<B=180-130
<B=50°
Answered by
1
Here is your answer....
Angle BAC = 180°- 110° [Linear pair]
= 70°
Now,
Angle BAC + x = Angle ACD [Exterior angle property]
=> 70 + x= 120
=> x = 120-70
=50°
And, Angle ACB = 180- angle ACD [Linear pair]
= 180°-120°
= 60°
Hope this helps you....
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