find the unknown angles marked in each of the following figures.
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Angle A = 75°
Angle B = 65°
In triangle ABC:-
A + B + ACB = 180°
75 + 65 + ACB = 180°
ACB = 180 - 140
Angle ACB = 40°
Angle ACB = Angle DCE {vertically opposite angle}
Angle DCE = 40°
In triangle CDE :-
C + D + E = 180°
40 + x + 110 = 180°
X = 180-150
X = 30°
Hope it helps.
Angle B = 65°
In triangle ABC:-
A + B + ACB = 180°
75 + 65 + ACB = 180°
ACB = 180 - 140
Angle ACB = 40°
Angle ACB = Angle DCE {vertically opposite angle}
Angle DCE = 40°
In triangle CDE :-
C + D + E = 180°
40 + x + 110 = 180°
X = 180-150
X = 30°
Hope it helps.
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