Math, asked by thakurdurgeshsingh, 11 months ago

find the unknown angles marked in each of the following figures.

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Answered by hdewangan
15
Angle A = 75°

Angle B = 65°

In triangle ABC:-

A + B + ACB = 180°

75 + 65 + ACB = 180°

ACB = 180 - 140

Angle ACB = 40°

Angle ACB = Angle DCE {vertically opposite angle}

Angle DCE = 40°

In triangle CDE :-

C + D + E = 180°

40 + x + 110 = 180°

X = 180-150

X = 30°

Hope it helps.

Answered by arysn2003
5
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