Question

Find the unknown angles of the triangle if the angles are given as ( x –2)⁰, (2x –3)⁰,(x+1)⁰

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Answer 1

Answer:

$( x - 2 ) + ( 2x-3) + (x+1 ) = 180\\\\x-2+2x-3+x+1=180\\\\4x-4=180\\\\4x=184\\\\x = 46$

Step-by-step explanation:

put x in the equation of angles

hope this helps

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\huge\bold{\green{Question}}$

Find the unknown angles of the triangle

if the angles are given as ( x –2)⁰, (2x

–3)⁰,(x+1)⁰.

$\huge\bold{\pink{AnSwer}}$

$\blue{{(x - 2) + (2x - 3) + (x + 1) = 180}}$

$\purple{x = \: x - 2 + 2x - 3 + x + 1 = 180}$

$\green{x = 4x - 4 = 180}$

Using Transpose Method:-

Subtraction becomes Addition and Multiplicative becomes Division

$\orange{4x = 184}$

$x = 46$

$\bold{\red{Question:-}}$

Find the unknown angles of the triangle if the angles are given as ( x –2)⁰, (2x –3)⁰,(x+1)⁰

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