Question

find the unknown length of X in the following figures​

Answer 1

Answer:

step by step explanation:

by using Pythagoras theorem,

$\Large{\mathsf{ \Rightarrow a^2 + b^2 = c^2}}$

$\Large{\mathsf{ \Rightarrow 7^2 + x^2 = 25^2}}$

$\Large{\mathsf{ \Rightarrow 49 + x^2 = 625}}$

$\Large{\mathsf{ \Rightarrow x^2 = 625-49}}$

$\Large{\mathsf{ \Rightarrow x^2 = 576}}$

$\Large{\mathsf{ \Rightarrow x = \sqrt{576}}}$

$\Large{\mathsf{ \Rightarrow x = 24}}$

Answer 2

$\tt {\underline{ \underline{ \purple{✠Answer:-}}}}$

Formula used:

$\tt{height= \sqrt{(hypo)²-(base)²} }$

Solution :

⋆ Let ABC is a triangle where AB= 25cm, BC= 7cm and CA= x cm

$\sf{ {x} = \sqrt{ {25}^{2} - {7}^{2} } }$

$⟹ \sf{ {x}^{} = \sqrt{625 - 49} }$

$⟹ \sf{x = \sqrt{576} }$

$⟹ \bf \red{x = 24}$

$\therefore \rm{The \: value \: of \: x \: is \: \red{24cm}. }$