Question

Find the value:
2√6÷(√2+√3) + 6√2÷(√6+3) - 8√3(√6+2)

Answer 1

2√6/(√2 + √3) + 6√2/(√6 + 3) - 8√3/(√6 + 2)

= 2√6/(√2 + √3) + 6√2/{√3(√2 + √3)} - 8√3/{√2(√3 + √2)}

=2√6/(√2 + √3) + (√3 ×√3 × 2√2)/{√3(√2 + √3)} - (4 ×√2 × √2 × √3)/{√2(√3 + √2)}

= 2√6/(√2 + √3) + (√3 × 2√2)/(√2 + √3) - 4 × √2 × √3/(√2 + √3)

=2√6/(√2 + √3) + 2√6/(√2 + √3) - 4√6/(√3 + √2)

= (2√6 + 2√6 - 4√6)/(√2 + √3)

= (4√6 - 4√6)/(√2 + √3)

= 0

hence, answer is 0.

Answer 2

Answer:

Step-by-step explanation:

yes