Question

FIND THE VALUE (3^0+4-^1)×2^2

Answer 1

=(3^0+4^-1)×2^2
=(1+1/4)×4
=(5/4)×4
=5

Answer 2

Hey there,

Your answer.

$= > (3 {}^{0} + 4 {}^{ - 1} ) \times 2 {}^{2} \\ \\ = > (1 + \frac{1}{4}) \times 4 \\ \\ = > ( \frac{4 + 1}{4}) \times 4 \\ \\ = > \frac{5}{4} \times 4 \\ \\ = > 5$


:-) Hope it helps !