find the value (3^-1+4^-1+5^-1)^0
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Answered by
3
Answer:
Given, 2[(2−1×4−1)÷2−2)
= 2[(2−1×4−1)÷2−2)
= 2[(21×41)÷41]
= 2[(21×41)÷41]
= 2[(81)÷41]
= 2[(81)×14]
= 2(21)
= 1
Answered by
0
Answer:
1
Step-by-step explanation:
(1/3+1/4+1/5)⁰
1
anything to the power zero is 1
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