Math, asked by arshiyab001, 3 months ago

find the value ׳+y³+z³+3×yz​

Answers

Answered by AmanASPIRANT
0

=0 (for all x=y=z)

Step-by-step explanation:

It is a identity

x^3+ y^3+ z^3 - 3xyz = 0

Ex. x=y=z= 4

64+64+64 - 3(64)=0

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