In triangle PQR,. Ps /QR,Ps=11cm, and area of triangle PQR=77 sq.cm If area of triangle PSR=3:4,find QS and SR
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Given : In triangle PQR,. Ps ⊥ QR, PS=11 cm, and area of triangle PQR=77 sq.cm
area of triangle PQS : area of triangle PSR : =3:4
To Find QS and SR
Solution:
area of triangle PQR= (1/2) * QR * PS
=> (1/2) * QR * 11 = 77
=> QR = 14 cm
area of triangle PQS = (1/2) QS * PS
area of triangle PSR = (1/2) SR * PS
(1/2) QS * PS : (1/2) SR * PS = 3: 4
=> QS : SR = 3 : 4
QS = 3x and SR = 4x
QS + SR = QR
=> 3x + 4x = 14
=> 7x = 14
=> x = 2
QS = 3x = 6
SR = 4x = 8
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