Question

find the value 4x^2+12xy+9y;x=-2,y=2

Answer 1

4x^2 +12xy+9y^2

(2x)^2 +2×2x×3y + (3y)^2

(2x+3y)^2
putting the values of x and y

=(2×-2 + 3×2)^2

= (-4 +6)^2

=(2)^2

=4