Find the value: a^3+8b^3+27c^3-18abc
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=a^3+(2b)^3+(3c)^3--3a(2b)(3c)
here fhe formula of
a^3+b^3+c^3--3abc
=(a+b+c)(a^2+b^2+c^2 -ab-bc-ca)
=(a+b+c){(a+b+c)^2-3(ab+bc+ca)}
here fhe formula of
a^3+b^3+c^3--3abc
=(a+b+c)(a^2+b^2+c^2 -ab-bc-ca)
=(a+b+c){(a+b+c)^2-3(ab+bc+ca)}
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here is your answer plzz like and mark as a brainlist answer
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