Question

Find the value a+b when ( 5+√3)/(7-4√3)=47a+√3b

Answer 1

already answered ..........................................

Answer 2

Hi friend,

We have to rationalize the denominator to know the value of a and b.

(5+√3)/(7-4√3)
=(5+√3)/(7-4√3)×(7+4√3)/(7+4√3)
=(5+√3)(7+4√3)/(7-4√3)(7+4√3)
=[35+20√3+7√3+4√3(√3)]/(7)²-(4√3)²
=(35+27√3+4(3))/49-16(3)
=(35+27√3+12)/49-48
=47+27√3/1
=47+27√3=47a+√3b

We can write it as 47(1)+√3(27)
So,a=1 and b=27

Hope it helps