Question

find the value
a³+b³+c³-3abc , where a=2,
b=3,c=3​

Answer 1

Answer:

8

Step-by-step explanation:

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

=(2+3+3)(4+9+9-6-6-9)

=(8)(1)

=8

Answer 2

Answer:

a³+b³+c³ -3abc

a=2, b=3,c=3 (given )

a³+b³+c³ =3abc

(2)³+ (3)³+ (3)³ = 3 × 2× 3 ×3

8 + 27 + 27 = 54

8+54 =54

8 +54-54=0

8

answer =8