find the value
a³+b³+c³-3abc , where a=2,
b=3,c=3
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Answered by
0
Answer:
8
Step-by-step explanation:
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
=(2+3+3)(4+9+9-6-6-9)
=(8)(1)
=8
Answered by
0
Answer:
a³+b³+c³ -3abc
a=2, b=3,c=3 (given )
a³+b³+c³ =3abc
(2)³+ (3)³+ (3)³ = 3 × 2× 3 ×3
8 + 27 + 27 = 54
8+54 =54
8 +54-54=0
8
answer =8
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